Question

How do you solve for r in `S=2πrh`?

Answer 1

`S/(2pih) = r`

Explanation:

Divide both sides by `2pih` to get `r` by itself on the right side:

`S/(2pih) = (cancel"2"cancel"pi"rcancel"h")/(cancel"2"cancel"pi"cancel"h")`

`S/(2pih) = r`