How do you solve for u in $8 u = 3 u + 35$ $8u=3u+35$ ?

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Answer 1 · 2018-04-23T08:56:03

$u = 7$ $u=7$

$8 u = 3 u + 35$ $8u= 3u + 35$

Subtract $3 u$ $3u$ from both sides

$8 u - 3 u = 5 u and 3 u - 3 u = 0 (0 u)$ $8u-3u=5u and 3u-3u= 0 (0u)$

So

$5 u = 35$ $5u= 35$

Divide both sides by $5$ $5$

$(5u)/5 = u \ "as" \ 5/5=1 and 35/5=7$

So

$u= 7$

How do you solve for u in 8u=3u+358u=3u+358u=3u+35?