# How do you solve for x: 3|2x − 1| − 4 = 29?

Aug 2, 2017

Solution : $x = 6 \mathmr{and} x = - 5$

#### Explanation:

1) $3 | 2 x - 1 | - 4 = 29 \mathmr{and} 3 | 2 x - 1 | = 29 + 4 \mathmr{and} | 2 x - 1 | = \frac{33}{3}$ or

$| 2 x - 1 | = 11 \mathmr{and} 2 x - 1 = 11 \mathmr{and} 2 x = 12 \mathmr{and} x = 6$ OR

2) $3 | 2 x - 1 | - 4 = 29 \mathmr{and} 3 | 2 x - 1 | = 29 + 4 \mathmr{and} | 2 x - 1 | = \frac{33}{3}$ or

$| 2 x - 1 | = 11 \mathmr{and} 2 x - 1 = - 11 \mathmr{and} 2 x = - 10 \mathmr{and} x = - 5$

Solution : $x = 6 \mathmr{and} x = - 5$ [Ans]

Aug 4, 2018

$x = 6$ and $x = - 5$

#### Explanation:

Let's start by adding $4$ to both sides to get

$3 | 2 x - 1 | = 33$

Next, we can divide both sides by $3$ to get

$| 2 x - 1 | = 11$

We have two different scenarios:

$2 x - 1 = 11$ and $2 x - 1 = - 11$

For both, we can add $1$ to both sides to get

$2 x = 12$ and $2 x = - 10$

Dividing both sides by $2$, we get

$x = 6$ and $x = - 5$

Hope this helps!