How do you solve for x: #5/x - 3 = 12#?

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Answer 1 · 2016-09-01T07:00:53

#x=1/3#

Given -

#5/x-3=12#

Multiply both sides by #x#

#(5/x-3)xx x=12 xx x#

#5-3x=12x#

Add #-5# on both sides

#cancel5-3xcancel(-5)=12x-5#
#-3x=12x-5#

Add #-12x #on both sides

#-3x-12x=cancel(12x)-5cancel(-12x)#

#-15x=-5#

Divide Both sides by #-15#

#(cancel(-15)x)/cancel(-15)=(-5)/(-15)#

#x=1/3#