Question

How do you solve for x in `2^ logx = 1/4`?

Answer 1

`x=0.01`

Explanation:

Note that
`color(white)("XXX")1/4=1/(2^2)=2^(-2)`

So if `2^(log(x)) = 1/4`
then
`color(white)("XXX")log(x)=-2`

`color(white)("XXX")10^(-2) = x` (based on definition of log)

`color(white)("XXX")x=1/100 = 0.01`