How do you solve for x in $In (e^x) = 0.442$ ?

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Answer 1 · 2016-04-14T16:40:28

0.442

The operators ln( ) and $e^( )$ are each the inverse of the other.

If O is an operator and $O^(-1)$ is its inverse, $O(O^(-1)(a))=a$
.
So, ln(e^(0.442))=0.442.

How do you solve for x in In (e^x) = 0.442In (e^x) = 0.442?