# How do you solve for x in #log_2x-log_2 3=5#?

##### 1 Answer

Feb 1, 2017

#### Explanation:

Let's first combine the left side, using the rule that

We can now set these as exponents to a base of 2 (to eliminate the log):

On the left side, this has the effect of taking the inverse function of the log and so cancels out, leaving:

And now let's check it:

(the logs are rounded to 3 decimal places)