Question

How do you solve for `x` in this equation `x^2 + 38 = 3x -12`?

Answer 1

No real roots

Explanation:

Bring the equation to standard form:
`y = x^2 - 3x + 50 = 0`
`D = d^2 = b^2 - 4ac = 9 - 200 = - 191`
Because D < 0, there are no real roots. There are 2 complex roots.