How do you solve for x in #x+1/2=3/4#?

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Answer 1 · 2018-03-04T23:35:53

See a solution process below:

First, put both fractions over common denominators:

#x + (2/2 xx 1/2) = 3/4#

#x + (2 xx 1)/(2 xx 2) = 3/4#

#x + 2/4 = 3/4#

Now, subtract #color(red)(2/4)# from each side of the equation to solve for #x# while keeping the equation balanced:

#x + 2/4 - color(red)(2/4) = 3/4 - color(red)(2/4)#

#x + 0 = (3 - color(red)(2))/4#

#x = 1/4#