How do you solve for y given #4x+y=2#?

1 Answer
Feb 12, 2017

Answer:

See the entire solution process below:

Explanation:

Step 1) Subtract #color(red)(4x)# from each side of the equation to solve for #y# while keeping the equation balanced:

#- color(red)(4x) + 4x + y = -color(red)(4x) + 2#

#0 + y = -4x + 2#

#y = -4x + 2#