Question

How do you solve for y in `8x-2y=6`?

Answer 1

See the entire solution process below:

Explanation:

Step 1) Subtract `color(red)(8x)` from each side of the equation to isolate the `y` term while keeping the equation balanced:

`-color(red)(8x) + 8x - 2y = -color(red)(8x) + 6`

`0 - 2y = -8x + 6`

`-2y = -8x + 6`

Now, divide each side of the equation by `color(red)(-2)` to solve for `y` while keeping the equation balanced:

`(-2y)/color(red)(-2) = (-8x + 6)/color(red)(-2)`

`(color(red)(cancel(color(black)(-2)))y)/cancel(color(red)(-2)) = (-8x)/color(red)(-2) + 6/color(red)(-2)`

`y = 4x - 3`