# How do you solve for y in 8x-2y=6 ?

Feb 13, 2017

See the entire solution process below:

#### Explanation:

Step 1) Subtract $\textcolor{red}{8 x}$ from each side of the equation to isolate the $y$ term while keeping the equation balanced:

$- \textcolor{red}{8 x} + 8 x - 2 y = - \textcolor{red}{8 x} + 6$

$0 - 2 y = - 8 x + 6$

$- 2 y = - 8 x + 6$

Now, divide each side of the equation by $\textcolor{red}{- 2}$ to solve for $y$ while keeping the equation balanced:

$\frac{- 2 y}{\textcolor{red}{- 2}} = \frac{- 8 x + 6}{\textcolor{red}{- 2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{- 2}}} y}{\cancel{\textcolor{red}{- 2}}} = \frac{- 8 x}{\textcolor{red}{- 2}} + \frac{6}{\textcolor{red}{- 2}}$

$y = 4 x - 3$