How do you solve for y in #8x-2y=6 #?

1 Answer
Feb 13, 2017

Answer:

See the entire solution process below:

Explanation:

Step 1) Subtract #color(red)(8x)# from each side of the equation to isolate the #y# term while keeping the equation balanced:

#-color(red)(8x) + 8x - 2y = -color(red)(8x) + 6#

#0 - 2y = -8x + 6#

#-2y = -8x + 6#

Now, divide each side of the equation by #color(red)(-2)# to solve for #y# while keeping the equation balanced:

#(-2y)/color(red)(-2) = (-8x + 6)/color(red)(-2)#

#(color(red)(cancel(color(black)(-2)))y)/cancel(color(red)(-2)) = (-8x)/color(red)(-2) + 6/color(red)(-2)#

#y = 4x - 3#