How do you solve for y in #Ax - By = C#?

1 Answer
Feb 16, 2016

Answer:

#y=(-C+Ax)/B#

Explanation:

We begin with #Ax-By=C#. Our goal is to isolate #y#, and the step I would do is to subtract #Ax# on both sides. If we do that, we have #-By=C-Ax#. From here we need to undo the #-B*y#, so we should divide by #-B#. Now, I like to break this up into two steps just so I don't make any silly mistakes. So first I divide by #-1# on both sides, which gives us #By=(C-Ax)/-1# or #Bx=-C+Ax#. Now I just divide by #B# on both sides, which leaves us with #y=(-C+Ax)/B#.