# How do you solve for y in ln y = 2x + 4?

Mar 19, 2018

#### Answer:

$y = {e}^{2 x + 4}$

#### Explanation:

We have:

$\ln y = 2 x + 4$

We can exponentiate (or if you prefer take anti-logarithms of) both side using base $e$, thus:

${e}^{\ln y} = {e}^{2 x + 4}$

Leading to:

$y = {e}^{2 x + 4}$