How do you solve for y in $ln y = 2 x + 4$ $ln y = 2x + 4$ ?

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Answer 1 · 2018-03-19T01:29:05

$y = e^{2 x + 4}$ $y = e^(2x+4)$

We have:

$ln y = 2 x + 4$ $ln y = 2x+4$

We can exponentiate (or if you prefer take anti-logarithms of) both side using base $e$ $e$ , thus:

$e^{ln y} = e^{2 x + 4}$ $e^(ln y) = e^(2x+4)$

Leading to:

$y = e^{2 x + 4}$ $y = e^(2x+4)$

How do you solve for y in lny=2x+4ln y = 2x + 4?