How do you solve #\frac { 1} { 3} + \frac { 1} { 2} n = 4#?

1 Answer
Nov 14, 2017

See a solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(6)# (the least common denominator for the two fractions) to eliminate the fractions while keeping the equation balanced:

#color(red)(6)(1/3 + 1/2n) = color(red)(6) xx 4#

#(color(red)(6) xx 1/3) + (color(red)(6) xx 1/2n) = 24#

#color(red)(6)/3 + color(red)(6)/2n = 24#

#2 + 3n = 24#

Next. subtract #color(red)(2)# from each side of the equation to isolate the #n# term while keeping the equation balanced:

#2 - color(red)(2) + 3n = 24 - color(red)(2)#

#0 + 3n = 22#

#3n = 22#

Now, divide each side of the equation by #color(red)(3)# to solve for #n# while keeping the equation balanced:

#(3n)/color(red)(3) = 22/color(red)(3)#

#(color(red)(cancel(color(black)(3)))n)/cancel(color(red)(3)) = 22/3#

#n = 22/3#