How do you solve #\frac { 1} { 3} x + 2= 16#?

1 Answer
Jul 16, 2017

See a solution process below:

Explanation:

Step 1) Subtract #color(red)(2)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#1/3x + 2 - color(red)(2) = 16 - color(red)(2)#

#1/3x + 0 = 14#

#1/3x = 14#

Step 2) Multiply each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#color(red)(3) xx 1/3x = color(red)(3) xx 14#

#cancel(color(red)(3)) xx 1/color(red)(cancel(color(black)(3)))x = 42#

#x = 42#