How do you solve #(\frac { 1} { 36} ) ^ { 6x - 3} = 6^ { 3x - 9}#?
1 Answer
Jan 24, 2017
Explanation:
Write in common bases:
#(6^-2)^(6x- 3) = 6^(3x -9)#
#6^(6 - 12x) = 6^(3x - 9)#
Eliminate the bases now:
#6 - 12x = 3x - 9#
#6 + 9 = 15x#
#x = 1#
Hopefully this helps!
