How do you solve $\frac{1}{5} = 5^{x - 1}$ $\frac { 1} { 5} = 5^ { x - 1}$ ?

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Answer 1 · 2016-12-18T16:32:31

$x = 0$ $x = 0$

$\frac{1}{a^{m}} = a^{- m}$ $1/a^m = a^-m$

$\frac{1}{5} = \frac{1}{5^{1}}$ $1/5 = 1/5^1$

$= 5^{- 1}$ $=5^-1$

substitute power for $x - 1$ $x - 1$ :

$x - 1 = - 1$ $x - 1 = -1$

add 1:

$x = 0$ $x = 0$

How do you solve 15=5x−1\frac { 1} { 5} = 5^ { x - 1}?