# How do you solve \frac { 1} { 5} x ^ { 2} - \frac { 29} { 25} x - \frac { 6} { 25} = 0?

Jul 20, 2017

$x = 6$ or $x = - \frac{1}{5}$

#### Explanation:

Step 1) First, let's make all the fractions have the same denominators:

$\frac{1}{5} {x}^{2} - \frac{29}{25} x - \frac{6}{25} = 0$

Becomes,

$\frac{5}{25} {x}^{2} - \frac{29}{25} x - \frac{6}{25} = 0$

Step 2) Then, make them as one fraction

$\frac{5 {x}^{2} - 29 x - 6}{25} = 0$

Step 3) Multiply both sides of the equation by $25$

$5 {x}^{2} - 29 x - 6 = 0$

Step 4) Factor

$5 {x}^{2} - 29 x - 6 = 0$

Becomes,

$\left(x - 6\right) \left(5 x + 1\right) = 0$

Step 5) Solve for x
$x = 6$ or $x = - \frac{1}{5}$