First, subtract #color(red)(1/6)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#1/x + 1/6 - color(red)(1/6) = 1/2 - color(red)(1/6)#
#1/x + 0 = (3/3 xx 1/2) - color(red)(1/6)#
#1/x = (3 xx 1)/(3 xx 2) - color(red)(1/6)#
#1/x = 3/6 - color(red)(1/6)#
#1/x = (3 - 1)/6#
#1/x = 2/6#
#1/x = (2 xx 1)/(2 xx 3)#
#1/x = (cancel(2) xx 1)/(cancel(2) xx 3)#
#1/x = 1/3#
Now, multiply each side of the equation by #3x# to eliminate the fractions and solve for #x# while keeping the equation balanced:
#3x * 1/x = 3x * 1/3#
#3color(red)(cancel(color(black)(x))) * 1/color(red)(cancel(color(black)(x))) = color(blue)(cancel(color(black)(3)))x * 1/color(blue)(cancel(color(black)(3)))#
#3 * 1 = x * 1#
#3 = x#
#x = 3#