How do you solve #\frac{2}{9} + \frac{2}{3} ( u - 5) + \frac{5}{9} u = \frac{2}{9} ( 5u + 4)#?

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Answer 1 · 2016-09-15T06:29:25

#u=36#

In #2/9+2/3(u-5)+5/9u=2/9(5u+4)#, we have as denominators #3# and #9#, whose GCD is #9#. Hence multiplying entire equation by #9#, we get

#9xx2/9+9xx2/3(u-5)+0xx5/9u=9xx2/9(5u+4)# or

#cancel9xx2/(cancel9)+3cancel9xx2/(cancel3)(u-5)+cancel9xx5/(cancel9)u=(cancel9xx2)/(cancel9)(5u+4)# or

#2+6(u-5)+5u=2(5u+4)# or

#2+6u-6xx5+5u=2xx5u+2xx4# or

#2+6u-30+5u=10u+8# or

#6u+5u-10u=8+30-2#

#u=38-2=36#