Question

How do you solve `(\frac { 3} { 5} ) ^ { x ^ { 2} - 7x - 8} = 1`?

Answer 1

`x=-1` or `8`

Explanation:

`(3/5)^(x^2-7x-8)=1=(3/5)^0`

i.e. `x^2-7x-8=0`

or `x^2-8x+x-8=0`

or `x(x-8)+1(x-8)=0`

or `(x+1)(x-8)=0`

i.e. `x=-1` or `8`