How do you solve #\frac{3x}{8} + 4\leq 0.2x + 5#?

Question

1166 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-06T23:23:05

#x<= 40/7#

#(3x)/8 +4 <= 0.2x +5#

Simplify #0.2x# to #x/5#.

#(3x)/8 <= x/5 +1#

#(3x)/8 - x/5 <= 1#

#(15x -8x)/40 <= 1#

#(7x)/40 <= 1#

#7x <= 40#

#x<= 40/7#

-Bub