How do you solve #\frac { 4w } { w + 8} + 6= \frac { 3} { w + 8}#?

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Answer 1 · 2018-07-08T04:39:13

#x=-9/2#

Multiplying by #w+8 ne 0#

#4w+6(w+8)=3#
expanding

#4w+6w+48=3#
collecting like Terms

#10w+48=3#
subtracing #48# on both sides

#10w=-45#
so #w=-9/2#

Answer 2 · 2018-07-08T16:51:15

#w=-9/2#

To get rid of the #w+8# in the denominator, we can multiply both sides by it. We now have the following equation:

#4w+6(w+8)=3#

We can distribute the #6# to the terms in the parenthesis to get

#4w+6w+48=3#

Combining our #w# terms on the left, we now have

#10w+48=3#

Subtract #48# from both sides to get

#10w=-45#

Dividing both sides by #10#, we get

#w=-45/10# or, in simplest form,

#w=-9/2#

Hope this helps!