How do you solve #\frac { 4z } { 7} - 8= 1#?

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Answer 1 · 2018-07-27T04:41:02

#z = 15.75#

#(4z)/7 - 8 = 1#

Add #color(blue)8# to both sides:
#(4z)/7 - 8 quadcolor(blue)(+quad8) = 1 quadcolor(blue)(+quad8)#

#(4z)/7 = 9#

Multiply both sides by #color(blue)(7)#:
#(4z)/7 color(blue)(*7) = 9 color(blue)(*7)#

#4z = 63#

Divide both sides by #color(blue)4#:
#(4z)/color(blue)4 = 63/color(blue)4#

#z = 15.75#

Hope this helps!