Question

How do you solve `\frac { 5 } { 8 } j = - 1 0`?

Answer 1

`j=-16`

Explanation:

As `5/8j=-10`

`5/8j÷5/8=-10÷5/8`

or `j=-10÷5/8`

Now dividing by `5/8` is equivalent to multiplying by its reciprocal i.e. multiplying by `8/5` and hence

`j=-10×8/5`

or `j=-(2×5)×8/5`

or `j=-(2×cancel5)×8/(1cancel5)`

or `j=-2×8`

or `j=-16`