How do you solve #\frac { 5x - 3} { 4} = 7#?

3 Answers
Mar 30, 2018

Answer:

#x=31/5#

Explanation:

#(5x-3)/4=7#

Cross multiply

#5x - 3= 7 xx 4#

#5x - 3= 28#

Then add #33# on both sides

#5x - 3 + 3 = 28 + 3#

#5x = 31#

#x = 31/5#

Mar 30, 2018

Answer:

#x=31/5#

Explanation:

#"to eliminate the fraction multiply both sides by 4"#

#cancel(4)^1xx(5x-3)/cancel(4)^1=4xx7#

#rArr5x-3=28#

#"add 3 to both sides"#

#5xcancel(-3)cancel(+3)=28+3#

#rArr5x=31#

#"divide both sides by 5"#

#(cancel(5) x)/cancel(5)=31/5#

#rArrx=31/5#

Aug 4, 2018

Answer:

#x=31/5#

Explanation:

To get rid of the #4# in the denominator, we can multiply both sides by #4# to get

#5x-3=28#

Next, add #3# to both sides to get

#5x=31#

Lastly, we can divide both sides by #5# to get

#x=31/5#

Hope this helps!