Question

How do you solve `\frac { 6} { 3} x - 4= 2x + 1`?

Answer 1

no solutions or `cancel(0)`

Explanation:

`6/3x - 4 = 2x + 1`

First, add `color(blue)4` to both sides of the equation:
`6/3x - 4 quadcolor(blue)(+quad4) = 2x + 1 quadcolor(blue)(+quad4)`

`6/3x = 2x + 5`

We also know that `6/3 = 2`.

`2x = 2x + 5`

Subtract `color(blue)(2x)` from both sides of the equation:
`2x quadcolor(blue)(-quad2x) = 2x + 5 quadcolor(blue)(-quad2x)`

`0 = 5`

Oh no! Now we don't have any more variables. We have to now see if this equation is true. `0` does NOT equal to `5`, so the answer is no solutions or `cancel(0)`.

Hope this helps!