First, multiply each side of the equation by #color(red)(12)# to eliminate the fractions while keeping the equation balanced:
#color(red)(12)((x - 1)/4 - x/3) = color(red)(12) xx 1/12#
#(color(red)(12) xx (x - 1)/4) - (color(red)(12) xx x/3) = cancel(color(red)(12)) xx 1/color(red)(cancel(color(black)(12)))#
#(cancel(color(red)(12))3 xx (x - 1)/color(red)(cancel(color(black)(4)))) - (cancel(color(red)(12))4 xx x/color(red)(cancel(color(black)(3)))) = 1#
#3(x - 1) - 4x = 1#
Next, expand the terms in parenthesis:
#(3 xx x) - (3 xx 1) - 4x = 1#
#3x - 3 - 4x = 1#
Then, group and combine like terms on the left side of the equation:
#3x - 4x - 3 = 1#
#(3 - 4)x - 3 = 1#
#-1x - 3 = 1#
Next, add #color(red)(3)# to each side of the equation to isolate the #x# term while keeping the equation balanced:
#-1x - 3 + color(red)(3) = 1 + color(red)(3)#
#-1x - 0 = 4#
#-1x = 4#
Now, multiply each side of the equation by #color(red)(-1)# to solve for #x# while keeping the equation balanced:
#color(red)(-1) xx -1x = color(red)(-1) xx 4#
#1x = -4#
#x = -4#