How do you solve #\frac{x^{2}-3x-28}{x}=x-7#?

1 Answer
Oct 16, 2017

#x=7#

Explanation:

Multiply both sides by #x# so you get rid of it as a denominator.

This will give you:
#x^2-3x-28=x(x-7)#
#x^2-3x-28=x^2-7x#

Move all the unknowns to one side and solve for #x#.
#x^2-x^2-3x+7x=28#
#cancel(x^2)-cancel(x^2)-3x+7x=28#
#4x=28#
#:.x=7#