# How do you solve \frac{x^{2}-3x-28}{x}=x-7?

Oct 16, 2017

$x = 7$

#### Explanation:

Multiply both sides by $x$ so you get rid of it as a denominator.

This will give you:
${x}^{2} - 3 x - 28 = x \left(x - 7\right)$
${x}^{2} - 3 x - 28 = {x}^{2} - 7 x$

Move all the unknowns to one side and solve for $x$.
${x}^{2} - {x}^{2} - 3 x + 7 x = 28$
$\cancel{{x}^{2}} - \cancel{{x}^{2}} - 3 x + 7 x = 28$
$4 x = 28$
$\therefore x = 7$