# How do you solve H= -0.5x^2 + x + 4 using the quadratic formula?

Apr 26, 2018

The answer ${x}_{1} = 1 + \sqrt{3}$ and ${x}_{2} = 1 - \sqrt{3}$

#### Explanation:

show the steps below

$- 0.5 {x}^{2} + x + 4 = 0$

Hit the two side by $- \frac{1}{0.5}$

${x}^{2} - \frac{x}{0.5} - 2 = 0$

$- 0.5 = - \frac{1}{2}$

${x}^{2} - 2 x - 2 = 0$

You can solve it by using the law:

${x}_{1} = \frac{- b + \sqrt{{b}^{2} - 4 a c}}{2 a}$

${x}_{2} = \frac{- b - \sqrt{{b}^{2} - 4 a c}}{2 a}$

in our formula the values of a b and c equal

$a = 1 , , , , , , b = - 2 , , , , , c = - 2$

${x}_{1} = \frac{2 + \sqrt{4 + 8}}{2}$

${x}_{1} = 1 + \sqrt{3}$

in the same way ${x}_{2}$ equal

${x}_{2} = 1 - \sqrt{3}$