How do you solve h = -16t^2 + 3200?

Jul 24, 2017

Solve for $h = 0$? $h =$maximum?

Explanation:

$h = 0$:
$0 = - 16 {t}^{2} + 3200 \to$
$16 {t}^{2} = 3200 \to {t}^{2} = \frac{3200}{16} = 200 \to$
${t}_{1 , 2} = \pm \sqrt{200} = \pm 10 \sqrt{2}$

$h =$maximum:
$\to t = 0 \to h = 3200$