Question

How do you solve `K_2PtCl_4 + NH_3 -> Pt(NH_3)_2Cl_2 + KCl`?

Answer 1

`K_2PtCl_4` `+ 2` `NH_3` `->` `Pt(NH_3)_2Cl_2` `+ 2` `KCl`

Explanation:

Start by counting the atoms on both sides of the equation:

L - Atom - R
2 - K - 1
1 - Pt - 1
4 - Cl - 3
1 - N - 2
3 - H - 6

Upon inspection, looks like only Pt is balanced on both sides ( L eft and R ight).

Start by placing a 2 in front of `KCl` since there are 2 K on the left, but only 1 K on the right. Doing so will balance out K and Cl.

Next, place a 2 in front of `NH_3` since there is 1 N on the left and 2 N on the right & 3 H on left and 6 H on right. Doing so will balance out N and H.

These 2 steps will balance the entire equation:
`K_2PtCl_4` `+ 2` `NH_3` `->` `Pt(NH_3)_2Cl_2` `+ 2` `KCl`

How to Balance Chemical Equation