How do you solve #K_2PtCl_4 + NH_3 -> Pt(NH_3)_2Cl_2 + KCl#?
Start by counting the atoms on both sides of the equation:
L - Atom - R
2 - K - 1
1 - Pt - 1
4 - Cl - 3
1 - N - 2
3 - H - 6
Upon inspection, looks like only Pt is balanced on both sides ( L eft and R ight).
Start by placing a 2 in front of
Next, place a 2 in front of
These 2 steps will balance the entire equation: