Question

How do you solve `ln (2x-5) = 3.78`?

Answer 1

I found: `x=(e^(3.78)+5)/2=24.41`

Explanation:

I would use the definition of log to change it into an exponential as:
`2x-5=e^(3.78)`
Rearranging:
`2x=e^(3.78)+5`
And:
`x=(e^(3.78)+5)/2=24.41`