# How do you solve ln(-4x-4)-ln3=3?

Aug 18, 2016

Use the rule $\ln x - \ln a = \ln \left(\frac{x}{a}\right)$:

$\implies \ln \left(\frac{- 4 x - 4}{3}\right) = 3$

$\implies \frac{- 4 x - 4}{3} = {e}^{3}$

$\implies - 4 x - 4 = 3 {e}^{3}$

$- 4 x = 3 {e}^{3} + 4$

$x = - \frac{1}{4} \left(3 {e}^{3} + 4\right)$

Hopefully this helps!