How do you solve #ln [((x+1) / x)]=1#?

1 Answer
May 2, 2018

Answer:

# x = 1/(e-1) #

Explanation:

We have:

# ln((x+1)/x) = 1 #

Therefore, by the definition of the logarithm, we have:

# (x+1)/x = e #

Which we now solve for #x#:

# x+1 = ex #

# :. (e-1)x = 1 #

Giving the solution:

# x = 1/(e-1) #