How do you solve #ln(x+12) - ln(x-2)=ln(x+1)-ln(x+11)#?

1 Answer
MattyMatty
Apr 29, 2018

#"No solution"#

Explanation:

#=> ln(x+12)+ln(x+11)=ln(x-2)+ln(x+1)#
#=> ln((x+12)(x+11)) = ln((x-2)(x+1))#
#=> ln(x^2+23 x+132) = ln(x^2-x-2)#
#=> cancel(x^2) + 23 x + 132 = cancel(x^2) - x - 2#
#=> 23 x + 132 = - x - 2#
#=> 24 x = -134#
#=> x = -134/24#
#=> x = -67/12#
#=> "No solution as x must be > 2 to be in the domain of all ln(.)"#

Related questions
See all questions in Logarithmic Models
Impact of this question
2455 views around the world
You can reuse this answer
Creative Commons License