Question

How do you solve `ln(x^2)=16`?

Answer 1

I found: `x=e^8=2,980.95`

Explanation:

We can use the property of the logs that allows you to take out the exponent of the argument and place it as multiplier in front of the log to get:

`2ln(x)=16`

rearrange:

`ln(x)=16/2=8`

use the definition of log to get:

`x=e^8=2,980.95`