How do you solve #ln(x-2)=2#?

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Answer 1 · 2016-11-08T07:07:01

The graph is here.

graph{ln(x-2)-2 [-53.33, 53.34, -26.67, 26.66]}

Answer 2 · 2016-11-08T07:50:32

#x=9.389#

#ln(x-2)=2#

#hArrx-2=e^2#

and #x=e^2+2=7.380+2=9.389#