How do you solve $Ln x^2=4$ ?

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Answer 1 · 2015-08-04T22:09:36

I found: $x=e^2=7.389$

You can use a property of the logs and write:
$lnx^2=2lnx$
so that you have:
$2lnx=4$
$lnx=4/2=2$
so that $x=e^2$

How do you solve Ln x^2=4Ln x^2=4?