How do you solve #Ln(x+2)+ln(x-2)=3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Bdub Mar 8, 2016 #x~~4.9# Explanation: #ln(x+2)+ln(x-2)=3# #ln[(x+2)(x-2)]=3#-> use property #log_bx+log_by=log_b(xy)# #ln (x^2-4) =3# #e^3=x^2-4#-> use definition #log_bx=n iffb^n=x# #e^3+4=x^2#-> solve for x #x=+-sqrt(e^3+4)# #x~~4.9, x~~#-4.9 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1260 views around the world You can reuse this answer Creative Commons License