How do you solve #ln x + 2ln4 = ln7 - ln x#?

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Answer 1 · 2016-02-02T11:37:03

#x=+sqrt7/4#

From the given:

#ln x+2 ln 4=ln 7 - ln x#

#ln x+ln x=ln 7-2 ln 4#

#2 ln x=ln 7-ln (4^2)#

#ln x^2=ln (7/16)#

#x^2=7/16#

#x=+-sqrt7/4# take the positive value as answer

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