How do you solve #ln x - ln (1/x) = 2#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Apr 27, 2018 #x=e# Explanation: As #lnx-ln(1/x)=2# we have #ln(x/(1/x))=2# or #lnx^2=2# or #2lnx=2# or #lnx=1# and #x=e# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1271 views around the world You can reuse this answer Creative Commons License