How do you solve #lnx=2#?

2 Answers
May 28, 2018

Answer:

#x=e^2#

Explanation:

Base-#e# cancels out with the natural log (#ln#) function, so we can apply it to both sides. We get

#e^(lnx)=e^2#

#cancel(e)^(cancel(ln)x)=e^2#

Notice base-#e# and #ln# cancel, and we're left with

#x=e^2#

as our final answer.

Hope this helps!

Jun 22, 2018

Answer:

#color(green)(x = e^2 = 7.389#

Explanation:

#ln x = 2#

http://slideplayer.com/slide/6865626/

#color(green)(x = e^2 = 7.389#