How do you solve #log_10 200!#?
Then by definition,
Now take the log on both sides and simplify using laws of logs to get
Use a computer package...
You can either ask a computer to evaluate
#log_10 (200!) = sum_(n=1)^200 log_10(n)#
Either way you have a large number of calculations to be done. The only advantage I can see of summing the logs of each number is that you will not have to deal with numbers larger than
Here are some computer generated figures: