Question

How do you solve `log_(121)x= 2`?

Answer 1

`x=14641`

Explanation:

Let's use both sides of the equation as exponents with a base `121`:
`121^(log_121(x)) = 121^2`

On the left, by definition of a logarithm we have just an unknown variable `x`:
`x = 121^2 = 14641`