How do you solve #log_2 3 + log_2 7 = log_2 x#?

1 Answer
EZ as pi
Jun 8, 2018

#x=21#

Explanation:

Use the addition law of logs.

"If logs are being added, then the numbers are being multiplied"

Note that the bases must be the same for this to apply.

#log_a b + log_a c = log_a(bxxc)#

#log_2 3+log_2 7 = log_2 (3xx7) = log_2 21#

#x=21#

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