How do you solve #log_2 (3x)>log_2 5#?

1 Answer
Eddie
Feb 9, 2017

See below :)

Explanation:

If the Socratic graphing utility wasn't so useless, one might be able to graph the log function here and show the whole picture.

But IF we assume that #log_(n) A > log_(n) B implies A > B# then we can say that, with your problem, #3x > 5 implies x > 5/3#

Desmos draws it thusly!

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