Question

How do you solve `log_2(x+2) - log_2x = 3`?

Answer 1

`x = 2/7`

Explanation:

Using log a - log b = `log(a/b)`,
`log_2((x+2)/x) = 3`
Inversely, `((x+2)/x)=2^3=8`
7x = 2.