How do you solve #log_2 (x) + log_2 (x+6) = 3#?
When you add two logs with the same base, based on the logarithm rules, it's the same as multiplying them.
To get rid of the log in order to isolate the variables:
Since there are no like terms, use the quadratic formula to solve:
ax + bx + c=0
Remember to check both answers to see if they work, by plugging them back into the original equation (if you do this you see that only