How do you solve #log_2 x - log_8 x = 4#?
You must first put in the same base. This can be started out by using the log rule
Now, rewrite the terms in the denominator by using the rule
Place on an equal denominator.
Now, you must use the rule
Convert to exponential form:
Checking the solution in the equation, we find that it works. Thus our solution set is
Hopefully this helps!